In the binary number "01011010", the rightmost value of "0" is a placeholder for __________.

In the binary number "01011010", the rightmost value of "0" is a placeholder for __________.

• A. 20
• B. 21
• C. 22
• D. 27

Answer: (A)

Binary numbers use place values that are powers of two. The rightmost digit is the least significant bit and sits at the 2^0 position, which is the ones place in decimal. So the rightmost 0 is the placeholder for the 2^0 weight. Since that bit is 0, it contributes nothing to the total value. Reading the eight bits as weights, the positions with 1s are 2^6 (64), 2^4 (16), 2^3 (8), and 2^1 (2); adding these gives 64 + 16 + 8 + 2 = 90. The key idea is that each bit’s place value is a power of two, and the rightmost position is always the 2^0 (ones) place.

Binary numbers use place values that are powers of two. The rightmost digit is the least significant bit and sits at the 2^0 position, which is the ones place in decimal. So the rightmost 0 is the placeholder for the 2^0 weight. Since that bit is 0, it contributes nothing to the total value. Reading the eight bits as weights, the positions with 1s are 2^6 (64), 2^4 (16), 2^3 (8), and 2^1 (2); adding these gives 64 + 16 + 8 + 2 = 90. The key idea is that each bit’s place value is a power of two, and the rightmost position is always the 2^0 (ones) place.